The Swamp

Posted: **Mon Feb 25, 2019 7:51 am**

So this was in an email newsletter I get....figured you would enjoy

The following clues contain two answers, both of which are anagrams of each other (ex. a light bulb goes off for the helper ="idea" and "aide"
1.) Boeing and Airbus CEO's position on exit
2.) A Buffett stock in fossil fuel
3.) Educators explain units of land measurement
4.) Going Gangnam style on your biggest competitor

Posted: **Mon Feb 25, 2019 9:01 am**

3. Teachers/Hectares
4. Viral/Rival

Posted: **Mon Feb 25, 2019 9:09 am**

Ryan wrote: ↑Mon Feb 25, 2019 9:01 am 3. Teachers/Hectares
4. Viral/Rival

yes
yes

Posted: **Mon Feb 25, 2019 9:11 am**

2) Cola/Coal

Posted: **Mon Feb 25, 2019 9:22 am**

Pruitt wrote: ↑Mon Feb 25, 2019 9:11 am2) Cola/Coal

yes

Posted: **Mon Feb 25, 2019 1:46 pm**

#1 is driving me crazy.

Posted: **Mon Feb 25, 2019 1:49 pm**

plane/Nepal (I got nothin')

Posted: **Mon Feb 25, 2019 2:46 pm**

Airplane/Ripe Anal

Posted: **Mon Feb 25, 2019 4:40 pm**

Airmen Remain

Posted: **Mon Feb 25, 2019 5:24 pm**

wlu_lax6 wrote: ↑Mon Feb 25, 2019 4:40 pmAirmen Remain

It should have been "position on Brexit."

I only point this out because I spent a good half hour working on it in an increasing fury...

Love these puzzles, any more you can share?

Posted: **Mon Feb 25, 2019 7:55 pm**

Pruitt wrote: ↑Mon Feb 25, 2019 5:24 pm
wlu_lax6 wrote: ↑Mon Feb 25, 2019 4:40 pmAirmen Remain
It should have been "position on Brexit."

I only point this out because I spent a good half hour working on it in an increasing fury...

Love these puzzles, any more you can share?

Not off hand, these were in a daily email I got for the first time today. If I get another set I will post.

Posted: **Mon Feb 25, 2019 8:38 pm**

wlu_lax6 wrote: ↑Mon Feb 25, 2019 4:40 pmAirmen Remain

That clue suced. Should have gone with Air Force servicemen's position on reenlisting.

Posted: **Mon Feb 25, 2019 8:40 pm**

Parachute spells nothing

Posted: **Fri Mar 01, 2019 9:31 am**

The same two letters can be placed before each of these words to make different words. What are these two letters?

one
edge
own
ought
awl
aught

Posted: **Fri Mar 01, 2019 9:37 am**

[+] spoiler: dr

Posted: **Fri Mar 01, 2019 12:13 pm**

Got it!

This makes me ridiculously proud of myself.

Posted: **Fri Mar 01, 2019 12:13 pm**

Do not go see dr acula.

Posted: **Tue Mar 05, 2019 11:39 am**

Math this time

A, B, C, D each represents a different digit from 1 to 9.

If ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?

Posted: **Tue Mar 05, 2019 11:46 am**

Are A, B, C, and D all different from each other?

Posted: **Tue Mar 05, 2019 12:18 pm**

wlu_lax6 wrote: ↑Tue Mar 05, 2019 11:39 am Math this time

A, B, C, D each represents a different digit from 1 to 9.

If ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?

[+] spoiler: 3861

Posted: **Tue Mar 05, 2019 12:54 pm**

phxgators wrote: ↑Tue Mar 05, 2019 12:18 pm
wlu_lax6 wrote: ↑Tue Mar 05, 2019 11:39 am Math this time

A, B, C, D each represents a different digit from 1 to 9.

If ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?

[+] spoiler
3861

I'm way more interested to find out how one figures this out than to find out what the answer actually is.

Posted: **Tue Mar 05, 2019 1:29 pm**

Steve of phpBB wrote: ↑Tue Mar 05, 2019 12:54 pm I'm way more interested to find out how one figures this out than to find out what the answer actually is.

My process for this:

[+] spoiler: Take any number and add the digits together (order does not matter), if the sum is divisible by 9 then the number is divisible by 9. (Ex: 1368 -> 1 + 3 + 6 + 8 = 18, 18 is divisible by 9, so 1368 is divisible by 9) So I started stepping through 4 digit numbers that were multiples of both 13 and 9, 1053 is the first. I shifted the digits checking for the other rules. I kept adding 117 (13*9) checking each one with unique digits. 1287 was the first to meet the first 3 requirements, but failed the last check. The next one to pass the first 3 checks was 2574, which just happens to be 1287*2. 2574 didn't work, but just started stepping by 1287 until I got the answer.

I realized after the fact that it was a multiple of 1287 because rotating the digits also does not affect divisibility by 11. Example: 1287, 2871, 8712, 7128 are all divisible by 11. So I could have stepped by 1287 (13*11*9) rather than 117.

Checking if divisible by 7 isn't quite as straightforward, but there might still be a way to directly get to the answer rather than doing manual checks. If someone has that step, I'd be interested in figuring that out.

ETA: This site has some more info on divisibility rules: https://www.mathsisfun.com/divisibility-rules.html

Posted: **Tue Mar 05, 2019 2:37 pm**

phxgators wrote: ↑Tue Mar 05, 2019 12:18 pm
wlu_lax6 wrote: ↑Tue Mar 05, 2019 11:39 am Math this time

A, B, C, D each represents a different digit from 1 to 9.

If ABCD is divisible by 13, BCDA is divisible by 11, CDAB is divisible by 9, and DABC is divisible by 7, what is the original number ABCD?

[+] spoiler
3861

correct

Posted: **Tue Mar 05, 2019 3:15 pm**

phxgators wrote: ↑Tue Mar 05, 2019 1:29 pm
Steve of phpBB wrote: ↑Tue Mar 05, 2019 12:54 pm I'm way more interested to find out how one figures this out than to find out what the answer actually is.
My process for this:

[+] spoiler
Take any number and add the digits together (order does not matter), if the sum is divisible by 9 then the number is divisible by 9. (Ex: 1368 -> 1 + 3 + 6 + 8 = 18, 18 is divisible by 9, so 1368 is divisible by 9) So I started stepping through 4 digit numbers that were multiples of both 13 and 9, 1053 is the first. I shifted the digits checking for the other rules. I kept adding 117 (13*9) checking each one with unique digits. 1287 was the first to meet the first 3 requirements, but failed the last check. The next one to pass the first 3 checks was 2574, which just happens to be 1287*2. 2574 didn't work, but just started stepping by 1287 until I got the answer.

I realized after the fact that it was a multiple of 1287 because rotating the digits also does not affect divisibility by 11. Example: 1287, 2871, 8712, 7128 are all divisible by 11. So I could have stepped by 1287 (13*11*9) rather than 117.

Checking if divisible by 7 isn't quite as straightforward, but there might still be a way to directly get to the answer rather than doing manual checks. If someone has that step, I'd be interested in figuring that out.

ETA: This site has some more info on divisibility rules: https://www.mathsisfun.com/divisibility-rules.html

Yeah,

[+] spoiler: I figured the first part out (about divisibility by 9). I wondered if there was a similar trick to doing the others, or if it was brute force trial and error.

About the fact that all six permutations of 1 2 8 7 are divisible by 11 - is that based on a principle, or again, just trial and error?

Posted: **Tue Mar 05, 2019 5:53 pm**

Steve of phpBB wrote: ↑Tue Mar 05, 2019 3:15 pm
Yeah,
[+] spoiler
I figured the first part out (about divisibility by 9). I wondered if there was a similar trick to doing the others, or if it was brute force trial and error.

About the fact that all six permutations of 1 2 8 7 are divisible by 11 - is that based on a principle, or again, just trial and error?

If I understand your question right,

[+] spoiler: rotating the digits 1287->2871->8712, etc, doesn't really change the alternating pattern the divisibility rules link mentions. I've seen the rule for 11 described a little differently but it comes out pretty much the same. Add alternating digits, compare the two sums. If the difference is a multiple of 11, the whole number is. So for 1287 1+8=9, 2+7=9. 9-9=0, which is divisible by 11. Rotating the digits in the number doesn't change those sums.

Posted: **Thu Mar 07, 2019 1:30 am**

I was told there would be no math.

Posted: **Fri Mar 08, 2019 8:18 am**

Today's puzzle comes courtesy of NPR Puzzlemaster Will Shortz and is dedicated to International Women's Day.

Take the 7-letter last name of a famous woman. Drop the letter E. Add an I and an F. You can rearrange the result to get a word that famously describes this woman. Who's the woman, and what's the word?

Posted: **Sun Mar 10, 2019 3:58 pm**

wlu_lax6 wrote: ↑Fri Mar 08, 2019 8:18 am Today's puzzle comes courtesy of NPR Puzzlemaster Will Shortz and is dedicated to International Women's Day.

Take the 7-letter last name of a famous woman. Drop the letter E. Add an I and an F. You can rearrange the result to get a word that famously describes this woman. Who's the woman, and what's the word?

Oprah Winfrey

wriffiny

Posted: **Sun Mar 10, 2019 4:01 pm**

I kid. I looked up the answer. Duh.

Posted: **Sun Mar 10, 2019 5:22 pm**

Beyonce Knowles - Wolfskin

Posted: **Mon Mar 11, 2019 7:03 am**

Answer
Gloria Steinem -> Feminist

Today's Q
>, <, or equal
The combined wealth of 98 Russian Billionaires // The entire Russian population's savings
JP Morgan CEO Jamie Dimon's 2017 pay package // Bryce Harper's 2019 pay from the Philadelphia Phillies
The number of day remaining until Brexit deadline // 18
U.S. GDP // U.S. national debt

Posted: **Mon Mar 11, 2019 8:54 am**

wlu_lax6 wrote: ↑Mon Mar 11, 2019 7:03 am Answer
Gloria Steinem -> Feminist

Today's Q
>, <, or equal
The combined wealth of 98 Russian Billionaires // The entire Russian population's savings
JP Morgan CEO Jamie Dimon's 2017 pay package // Bryce Harper's 2019 pay from the Philadelphia Phillies
The number of day remaining until Brexit deadline // 18
U.S. GDP // U.S. national debt

>
>
<
>

(All guesses except #3)

Posted: **Fri Mar 15, 2019 6:51 am**

It was >, <, =, <

I give you a Shakespeare quote, and you’ll have to determine which play it’s from.
1. “What’s in a name? A rose by any name would smell as sweet.”
2. “Lord, what fools these mortals be!”
3. “There is nothing either good or bad, but thinking makes it so.”
4. “The fault, dear Brutus, is not in our stars, but in ourselves, that we are underlings.”
5. “Some are born great, some achieve greatness, and some have greatness thrust upon them.”

Posted: **Fri Mar 15, 2019 8:30 am**

#2 - Midsummer night's dream

Posted: **Fri Mar 15, 2019 8:53 am**

Johnny Carwash wrote: ↑Fri Mar 15, 2019 8:30 am #2 - Midsummer night's dream

yes

Posted: **Fri Mar 15, 2019 8:55 am**

1. Romeo and Juliet

Posted: **Fri Mar 15, 2019 8:55 am**

govmentchedda wrote: ↑Fri Mar 15, 2019 8:55 am 1. Romeo and Juliet

of course

Posted: **Fri Mar 15, 2019 9:08 am**

4. Julius Caesar

[+] spoiler: 1. Midsummer 2. Romeo and Juliet 3. MacBeth 4. Julius Caesar 5. Hamlet

Posted: **Fri Mar 15, 2019 9:15 am**

govmentchedda wrote: ↑Fri Mar 15, 2019 9:08 am 4. Julius Caesar

[+] spoiler
1. Midsummer 2. Romeo and Juliet 3. MacBeth 4. Julius Caesar 5. Hamlet

well done sir

Posted: **Fri Mar 15, 2019 9:29 am**

wlu_lax6 wrote: ↑Fri Mar 15, 2019 9:15 am
govmentchedda wrote: ↑Fri Mar 15, 2019 9:08 am 4. Julius Caesar

[+] spoiler
1. Midsummer 2. Romeo and Juliet 3. MacBeth 4. Julius Caesar 5. Hamlet

well done sir

Merci

[+] spoiler: I only had Midsummer from Carwash. Great movie though.

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